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SAT Math: Distributing Terms to Find the Coefficient of x 2 Views


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Description:

Given the following equation where a, b, and c are constants, what is the value of b?


Transcript

00:00

Yeah Whoa Okay CT mash bumpers Another weird quadratic equation

00:07

for you here We got this thing given the following

00:09

equation where a B and C are constants with the

00:12

value of B All right so we're trying to find

00:17

this term here in all this mess Well the left

00:20

side of the equation has two identical parent testicles Do

00:22

we smell some factoring in our future We love the

00:26

smell of factoring in the morning All right So we're

00:30

gonna slow down here and think about our end goal

00:32

We want to see what be equal So we need

00:35

to multiply out everything on the left side and see

00:37

what coefficient is glued to the ex term Sure we

00:40

could factor then distribute then combined like terms But like

00:43

why let's cut out the middleman here And be sure

00:46

you used this safe the scissors and just jump right

00:48

to the distributing You gotta remember what we're solving here

00:51

And time matters These tests are times right So let's

00:54

just distribute everything out here we've got here is primary

00:58

equations We got ten x squared We must buy that

01:00

five accident to X and then we've got forty x

01:04

there and then six x there And it was three

01:08

times twenty four equals that X word Bxc OK then

01:11

we kind of combined some terms here We got ten

01:13

x squared plus forty six Acts plus 24 so and

01:18

this is all great but the only term we really

01:20

care about is the coefficient of X right there which

01:23

is B It's forty six That's it We're done answers 00:01:26.82 --> [endTime] Forty six No

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