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SAT Math 1.3 Geometry and Measurement. Find the length of CE.
SAT Math 3.4 Geometry and Measurement 213 Views
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Description:
SAT Math 3.4 Geometry and Measurement
- Triangles / Right Triangles and Pythagorean Theorem
- Product Type / SAT Math
- Geometry / Define trigonometric ratios and solve problems involving right triangles
- Similarity, Right Triangles, and Trigonometry / Define trigonometric ratios and solve right triangle problems
- Additional Topics in Math / Right triangle trigonometry
Transcript
- 00:02
Here’s your shmoop du jour, brought to you by missing values.
- 00:06
Charles Manson could teach a master class on the subject.
- 00:10
What is the value of x in this figure?
- 00:12
And here are the potential answers...
- 00:15
Okay, so what we have here is a tale of two right triangles.
Full Transcript
- 00:19
Let’s start with the bigger of the two.
- 00:21
The hypotenuse is 11…one leg is the dotted vertical line, or the height,
- 00:26
and the other leg is 6 plus x… whatever “x” is.
- 00:29
The smaller triangle has a hypotenuse of 7, the same height, and plain ol’ x as its base.
- 00:35
So, of course, because we’re dealing with triangles, we can use the
- 00:38
Pythagorean Theorem to solve for the missing leg, x
- 00:41
For the bigger triangle, (x + 6) squared + h squared = 11 squared.
- 00:47
For the smaller one, x squared + h squared = 7 squared.
- 00:51
We can simplify the second one a bit....
- 00:53
So now we have x squared + h squared = 49.
- 00:57
By subtracting x squared from both sides, we now have h squared = 49 - x squared…
- 01:02
…and we can now take the second part – the 49 minus x squared…
- 01:06
…and use it to replace the h squared in our first equation…
- 01:10
…giving us x squared + 12x + 36 + (49 - x squared) = 121.
- 01:23
We can add together our 36 and 49, like this…
- 01:26
…and our two x squareds cancel out…
- 01:27
…giving us 12x + 85 = 121.
- 01:30
We’ll knock 85 off both sides to get 12x = 36…
- 01:34
…and finally divide both sides by 12 to get x = 3.
- 01:38
Choice B.
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